JEE Main 12 Jan 2019 Evening Question 29

Question: The correct order of atomic radii is

[JEE Main Online Paper Held On 12-Jan-2019 Evening]

Options:

A) $ Ce>Eu>Ho>N $

B) $ Ho>N>Eu>Ce $

C) $ Eu>Ce>Ho>N $

D) $ N>Ce>Eu>Ho $

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Answer:

Correct Answer: C

Solution:

  • Given elements are:$ Ce, Eu, Ho, N$
    We have to find the correct order of atomic radii.
    Cerium $(Ce)$, europium $(Eu)$ and Holmium $(Ho)$ are lanthanide elements.
    Their metallic radius is: $Ce$ = 181.8 pm $Eu$ = 208.4 pm $Ho$ = 176.2 pm
    Atomic radius of nitrogen $(N)$ = 65 pm.
    Thus, the atomic radii follow the order:Eu > Ce > Ho > N.
    Hence, the correct option is $(C)$.