JEE Main 12 Jan 2019 Evening Question 15
Question: Given:
(i) $ {C _{(graphite)}}+{O _{2(g)}}\to C{O _{2(g)}};{\Delta_r}H^{o}=xkJ,mo{l^{-1}} $
(ii) $ {C _{(graphite)}}+\frac{1}{2}{O _{2(g)}}\to C{O _{(g)}}; $ $ {\Delta_r}H^{o}=ykJmo{l^{-1}} $
(iii) $ C{O _{(g)}}+\frac{1}{2}{O _{2(g)}}\to {CO _2} _{(g)};{\Delta_r}H^{o}=zkJmo{l^{-1}} $
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
[JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ z=x+y $
B) $ x=y-z $
C) $ x=y+z $
D) $ y=2zx $
Show Answer
Answer:
Correct Answer: C
Solution:
- By adding equation (ii) and (iii), we get $ C(graphite)+{O _{2(g)}}\to C{O _{2(g)}}, $ i.e., $ x=y+z $
