JEE Main Solved Paper 2017 Question 23
Question: In the above circuit the current in each resistance is: JEE Main Solved Paper-2017
Options:
A) 0.5
B) 0 A
C) 1 A
D) 0.25 A
Show Answer
Answer:
Correct Answer: B
Solution:
$ \text{Kirchoff’s voltage law in loop 1:}$
$-2 + 2 + (i_1 - i_2) \cdot 1 = 0$
$ \text{This implies that } i_1 - i_2 = 0 \text{ or } i_1 = i_2 \text{ — (1)}$
$ \text{Kirchoff’s Voltage law in loop 2:}$
$-2 + (i_2 - i_1) \cdot 1 + 2 + (i_2 - i_3) \cdot 1 = 0$
$ \text{This implies that } i_2 - i_3 = 0 \text{ or } i_2 = i_3 \text{ — (2)}$
$ \text{Kirchoff’s Voltage law in loop 3:}$
$-2 + (i_3 - i_2) \cdot 1 + 2 + (i_3 - i_1) \cdot 1 = 0$
$ \text{This implies that } i_3 = 0$
$ \text{From (2) we get } i_2 = i_3 = 0$
$ \text{From (1) we get } i_1 = i_2 = 0$
$\Rightarrow i_1 = i_2 = i_3 = 0$
