JEE Main On 8 April 2017 Question 21
Question: Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity? [JEE Online 08-04-2017]
Options:
A)
B)
C)
D)
Show Answer
Answer:
Correct Answer: C
Solution:
- a = -C $ \frac{VdV}{dx}=-C $ $ VdV=-CdX $ $ \frac{V^{2}}{2}=-Cx+k $ $ x=-\frac{V^{2}}{2C}+\frac{K}{C} $