JEE Main On 8 April 2017 Question 21

Question: Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity? [JEE Online 08-04-2017]

Options:

A)

B)

C)

D)

Show Answer

Answer:

Correct Answer: C

Solution:

  • a = -C $ \frac{VdV}{dx}=-C $ $ VdV=-CdX $ $ \frac{V^{2}}{2}=-Cx+k $ $ x=-\frac{V^{2}}{2C}+\frac{K}{C} $