JEE Main On 8 April 2017 Question 14
Question: There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between in limits 589.0V to 589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of $ 60{}^\circ $ with the direction of the field? [JEE Online 08-04-2017]
Options:
A) 589.4 V
B) 589.5 V
C) 589.2 V
D) 589.6 V
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \Delta V=E.d $ 0.8 = Ed (max) $ \Delta V=Ed\cos \theta =0.8\times \cos 60 $ = 0.4 +589.0 =589.4
