Area Of Triangle
Area of Triangle
The area of a triangle is a measure of the amount of space enclosed by the triangle’s sides. It is calculated by multiplying the length of the triangle’s base by its height and then dividing the result by two. The base of a triangle is any side of the triangle, and the height is the perpendicular distance from the base to the opposite vertex. The area of a triangle can also be calculated using Heron’s formula, which uses the lengths of the triangle’s sides to calculate its area. The area of a triangle is important in many applications, such as measuring the size of a piece of land or calculating the volume of a pyramid.
What is the Area of a Triangle?
Area of a Triangle
The area of a triangle is a measure of the amount of space enclosed by the triangle’s sides. It is measured in square units, such as square inches, square centimeters, or square meters.
There are several formulas for calculating the area of a triangle. The most common formula is:
Area = (1/2) * base * height
where:
 base is the length of one side of the triangle
 height is the length of the altitude from the base to the opposite vertex
For example, if a triangle has a base of 6 inches and a height of 4 inches, then its area is:
Area = (1/2) * 6 inches * 4 inches = 12 square inches
Other Formulas for the Area of a Triangle
In addition to the basic formula, there are several other formulas that can be used to calculate the area of a triangle. These formulas include:
 Heron’s formula:
Area = √(s(s  a)(s  b)(s  c))
where:

s is the semiperimeter of the triangle, which is equal to half the sum of the lengths of the three sides

a, b, and c are the lengths of the three sides of the triangle

Brahmagupta’s formula:
Area = √((s  a)(s  b)(s  c)(s  d))
where:
 s is the semiperimeter of the triangle
 a, b, c, and d are the lengths of the four sides of a cyclic quadrilateral, which is a quadrilateral that can be inscribed in a circle
Examples
Here are some examples of how to calculate the area of a triangle using different formulas:
 Example 1: A triangle has a base of 6 inches and a height of 4 inches. What is its area?
Area = (1/2) * 6 inches * 4 inches = 12 square inches
 Example 2: A triangle has sides of length 5 inches, 7 inches, and 8 inches. What is its area?
s = (5 inches + 7 inches + 8 inches) / 2 = 10 inches
Area = √(10 inches * 5 inches * 3 inches * 2 inches) = 14.6969 square inches
 Example 3: A cyclic quadrilateral has sides of length 4 inches, 6 inches, 8 inches, and 10 inches. What is the area of the triangle formed by the diagonals of the quadrilateral?
s = (4 inches + 6 inches + 8 inches + 10 inches) / 2 = 14 inches
Area = √((14 inches  4 inches)(14 inches  6 inches)(14 inches  8 inches)(14 inches  10 inches)) = 24 square inches
Area of a Triangle Formula
Area of a Triangle Formula
The area of a triangle is given by the formula:
A = (1/2) * b * h
where:
 A is the area of the triangle in square units
 b is the length of the base of the triangle in units
 h is the height of the triangle in units
Example 1
Find the area of a triangle with a base of 6 inches and a height of 8 inches.
A = (1/2) * 6 in * 8 in
A = 24 square inches
Example 2
Find the area of a triangle with a base of 10 centimeters and a height of 15 centimeters.
A = (1/2) * 10 cm * 15 cm
A = 75 square centimeters
Example 3
Find the area of a triangle with a base of 2.5 meters and a height of 4 meters.
A = (1/2) * 2.5 m * 4 m
A = 5 square meters
Applications of the Area of a Triangle Formula
The area of a triangle formula is used in a variety of applications, including:
 Finding the area of a piece of land
 Finding the area of a roof
 Finding the area of a sail
 Finding the area of a window
 Finding the area of a flag
The area of a triangle formula is a basic formula that is used in a variety of applications. It is important to understand how to use this formula in order to solve problems involving the area of a triangle.
Area of a Right Angled Triangle
The area of a rightangled triangle is calculated using the formula:
Area = (1/2) * base * height
where:
 base is the length of the side adjacent to the right angle
 height is the length of the side opposite the right angle
For example, if a rightangled triangle has a base of 6 cm and a height of 8 cm, then its area would be:
Area = (1/2) * 6 cm * 8 cm = 24 cm²
Here are some additional examples of how to calculate the area of a rightangled triangle:
 A rightangled triangle with a base of 4 cm and a height of 3 cm has an area of 6 cm².
 A rightangled triangle with a base of 5 cm and a height of 12 cm has an area of 30 cm².
 A rightangled triangle with a base of 8 cm and a height of 10 cm has an area of 40 cm².
The area of a rightangled triangle can also be found using the Pythagorean theorem, which states that in a rightangled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
For example, if a rightangled triangle has a base of 6 cm and a height of 8 cm, then the hypotenuse can be found using the Pythagorean theorem:
c² = a² + b²
c² = 6² + 8²
c² = 36 + 64
c² = 100
c = √100
c = 10 cm
The area of the triangle can then be found using the formula:
Area = (1/2) * base * height
Area = (1/2) * 6 cm * 8 cm = 24 cm²
The area of a rightangled triangle can be used to find the area of other shapes, such as rectangles, squares, and parallelograms. For example, the area of a rectangle is equal to the product of its length and width, and the area of a square is equal to the square of its side length.
Area of an Equilateral Triangle
Area of an Equilateral Triangle
An equilateral triangle is a triangle in which all three sides are of equal length. The area of an equilateral triangle can be calculated using the following formula:
Area = (√3 / 4) * s^2
where:
 s is the length of one side of the equilateral triangle
Example:
If the length of one side of an equilateral triangle is 6 cm, then the area of the triangle is:
Area = (√3 / 4) * 6^2
Area = (√3 / 4) * 36
Area = 9√3 cm^2
Proof:
The area of an equilateral triangle can also be derived using the following steps:
 Divide the equilateral triangle into two congruent 306090 triangles by drawing one of the altitudes of the triangle.
 The base of each 306090 triangle is half the length of one side of the equilateral triangle, and the height of each triangle is √3 times half the length of one side of the equilateral triangle.
 The area of each 306090 triangle is therefore:
Area = (1 / 2) * (s / 2) * (√3 / 2) * s
Area = (√3 / 4) * s^2
 The area of the equilateral triangle is therefore twice the area of one of the 306090 triangles:
Area = 2 * (√3 / 4) * s^2
Area = (√3 / 2) * s^2
Applications:
The area of an equilateral triangle is used in a variety of applications, including:
 Calculating the area of a regular polygon
 Calculating the volume of a regular pyramid
 Calculating the surface area of a regular tetrahedron
 Calculating the area of a rhombus
 Calculating the area of a hexagon
Area of an Isosceles Triangle
Area of an Isosceles Triangle
An isosceles triangle is a triangle with two equal sides. The area of an isosceles triangle can be calculated using the following formula:
Area = (1/2) * base * height
where:
 base is the length of one of the equal sides of the triangle
 height is the length of the altitude drawn from the vertex opposite the base
Example 1:
An isosceles triangle has a base of 6 cm and a height of 4 cm. What is the area of the triangle?
Area = (1/2) * 6 cm * 4 cm
Area = 12 cm^2
Example 2:
An isosceles triangle has equal sides of 8 cm each and an altitude of 5 cm. What is the area of the triangle?
Area = (1/2) * 8 cm * 5 cm
Area = 20 cm^2
Properties of Isosceles Triangles:
 The base angles of an isosceles triangle are equal.
 The altitude of an isosceles triangle bisects the base.
 The sum of the base angles of an isosceles triangle is 180 degrees.
 The area of an isosceles triangle is equal to half the product of the base and the height.
Perimeter of a Triangle
The perimeter of a triangle is the sum of the lengths of all three sides. It can be calculated using the formula:
Perimeter = Side 1 + Side 2 + Side 3
For example, if a triangle has sides of length 3 cm, 4 cm, and 5 cm, then its perimeter would be:
Perimeter = 3 cm + 4 cm + 5 cm = 12 cm
Here are some additional examples of how to calculate the perimeter of a triangle:
 A triangle with sides of length 6 cm, 8 cm, and 10 cm has a perimeter of 24 cm.
 A triangle with sides of length 12 cm, 15 cm, and 18 cm has a perimeter of 45 cm.
 A triangle with sides of length 20 cm, 25 cm, and 30 cm has a perimeter of 75 cm.
The perimeter of a triangle is a basic geometric concept that can be used to solve a variety of problems. For example, it can be used to find the length of a missing side of a triangle, or to determine whether a triangle is equilateral, isosceles, or scalene.
Area of Triangle with Three Sides (Heron’s Formula)
Heron’s Formula
Heron’s formula is a mathematical formula that allows you to calculate the area of a triangle when you know the lengths of its three sides. It is named after the Greek mathematician Heron of Alexandria, who lived in the 1st century AD.
The formula is as follows:
Area = √(s(s  a)(s  b)(s  c))
where:
 s is the semiperimeter of the triangle, which is half the sum of its three sides
 a, b, and c are the lengths of the three sides of the triangle
Example:
Let’s say you have a triangle with sides of length 3, 4, and 5. To find the area of this triangle, you would first calculate the semiperimeter:
s = (3 + 4 + 5) / 2 = 6
Then, you would plug the values of s, a, b, and c into the Heron’s formula:
Area = √(6(6  3)(6  4)(6  5)) = √(6 * 3 * 2 * 1) = 6
Therefore, the area of the triangle is 6 square units.
Proof:
Heron’s formula can be proven using a variety of methods. One common proof involves using the law of cosines to find the length of the altitude of the triangle. The altitude is then used to calculate the area of the triangle.
Here is a proof of Heron’s formula using the law of cosines:
Let ABC be a triangle with sides of length a, b, and c. Let h be the altitude from vertex A to side BC. Then, by the law of cosines, we have:
h^2 = c^2  (b^2 + a^2  2ab cos(C))
where C is the angle opposite side c.
We can also use the law of sines to find the area of the triangle:
Area = (1/2)ab sin(C)
Substituting the expression for h^2 from the law of cosines into the expression for the area, we get:
Area = (1/2)ab √(1  (b^2 + a^2  2ab cos(C))/c^2)
Simplifying this expression, we get:
Area = (1/2)ab √((c^2  b^2  a^2 + 2ab cos(C))/c^2)
Factoring the numerator of the square root, we get:
Area = (1/2)ab √((c  b + a)(c + b  a))/c^2)
Since c  b + a = 2s  b and c + b  a = 2s  a, we can rewrite the expression as:
Area = (1/2)ab √((2s  b)(2s  a))/c^2)
Multiplying both the numerator and denominator by 2, we get:
Area = (1/4)ab √(4s(s  a)(s  b)(s  c))/c^2)
Since 4s(s  a)(s  b)(s  c) = 16s^2  4s(a^2 + b^2 + c^2) + 4abc, we can rewrite the expression as:
Area = (1/4)ab √(16s^2  4s(a^2 + b^2 + c^2) + 4abc)/c^2)
Since a^2 + b^2 + c^2 = 2s^2, we can rewrite the expression as:
Area = (1/4)ab √(16s^2  8s^2 + 4abc)/c^2)
Simplifying this expression, we get:
Area = (1/4)ab √(8s(s  a)(s  b)(s  c))/c^2)
Multiplying both the numerator and denominator by 4, we get:
Area = √(s(s  a)(s  b)(s  c))
which is Heron’s formula.
Area of a Triangle Given Two Sides and the Included Angle (SAS)
Area of a Triangle Given Two Sides and the Included Angle (SAS)
The area of a triangle can be calculated using the formula:
Area = (1/2) * b * c * sin(A)
where:
 b and c are the lengths of two sides of the triangle
 A is the angle between the two sides
Example:
Find the area of a triangle with sides of length 5 cm and 7 cm, and an angle of 30 degrees between the sides.
Area = (1/2) * 5 cm * 7 cm * sin(30 degrees)
Area = (1/2) * 35 cm^2 * 0.5
Area = 8.75 cm^2
Proof:
The formula for the area of a triangle can be derived using trigonometry.
Consider a triangle with sides of length a, b, and c, and an angle A between sides a and b.
The area of the triangle is given by:
Area = (1/2) * b * h
where h is the height of the triangle.
The height of the triangle can be found using the sine function:
h = b * sin(A)
Substituting this into the formula for the area, we get:
Area = (1/2) * b * b * sin(A)
Simplifying, we get:
Area = (1/2) * b^2 * sin(A)
This is the formula for the area of a triangle given two sides and the included angle.
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Area of a Triangle Solved Examples
Area of a Triangle Solved Examples
The area of a triangle is given by the formula:
A = (1/2) * b * h
where:
 A is the area of the triangle in square units
 b is the length of the base of the triangle in units
 h is the height of the triangle in units
Example 1:
Find the area of a triangle with a base of 6 cm and a height of 8 cm.
A = (1/2) * b * h
A = (1/2) * 6 cm * 8 cm
A = 24 cm^2
Therefore, the area of the triangle is 24 square centimeters.
Example 2:
Find the area of a triangle with a base of 10 inches and a height of 12 inches.
A = (1/2) * b * h
A = (1/2) * 10 inches * 12 inches
A = 60 square inches
Therefore, the area of the triangle is 60 square inches.
Example 3:
Find the area of a triangle with a base of 3 meters and a height of 4 meters.
A = (1/2) * b * h
A = (1/2) * 3 meters * 4 meters
A = 6 square meters
Therefore, the area of the triangle is 6 square meters.
Frequently Asked Questions on Area of a Triangle
What is the area of a triangle?
The area of a triangle is a measure of the amount of twodimensional space enclosed by the triangle. It is a fundamental concept in geometry and has various applications in different fields. The area of a triangle can be calculated using different formulas, depending on the given information.
Formula 1: Base and Height The most common formula for finding the area of a triangle is using its base and height. The base is the length of one side of the triangle, and the height is the perpendicular distance from the base to the opposite vertex.
Area = (1/2) * Base * Height
Example: Consider a triangle with a base of 6 units and a height of 4 units.
Area = (1/2) * 6 * 4 Area = 12 square units
Formula 2: Heron’s Formula Heron’s formula is used when the lengths of all three sides of a triangle are known. It is named after the Greek mathematician Heron of Alexandria.
Area = √[s(s  a)(s  b)(s  c)]
where: s = semiperimeter = (a + b + c) / 2 a, b, c = lengths of the three sides of the triangle
Example: Consider a triangle with sides of lengths 5 units, 7 units, and 8 units.
s = (5 + 7 + 8) / 2 = 10 Area = √[10(10  5)(10  7)(10  8)] Area = √[10 * 5 * 3 * 2] Area = √300 Area ≈ 17.32 square units
Formula 3: Coordinates of Vertices If the coordinates of the vertices of a triangle are known, the area can be calculated using the determinant of a matrix.
Area = (1/2) * x1(y2  y3) + x2(y3  y1) + x3(y1  y2)
where: (x1, y1), (x2, y2), (x3, y3) are the coordinates of the three vertices
Example: Consider a triangle with vertices A(2, 3), B(4, 6), and C(6, 2).
Area = (1/2) * 2(6  2) + 4(2  3) + 6(3  6) Area = (1/2) * 2(4) + 4(1) + 6(3) Area = (1/2) * 8  4  18 Area = (1/2) * 14 Area = 7 square units
These are just a few of the formulas used to calculate the area of a triangle. The choice of formula depends on the information available about the triangle. Understanding these formulas is essential for solving various geometry problems and applications in fields such as engineering, architecture, and surveying.
What is the area when two sides of a triangle and included angle are given?
The area of a triangle when two sides and the included angle are given can be calculated using the formula:
Area = (1/2) * b * c * sin(A)
where: b and c are the lengths of the two given sides A is the measure of the included angle
For example, if we have a triangle with sides of length 5 cm and 7 cm, and the included angle is 60 degrees, the area of the triangle would be:
Area = (1/2) * 5 cm * 7 cm * sin(60 degrees) = (1/2) * 35 cm^2 * 0.866 = 15.075 cm^2
Here are some additional examples:
If we have a triangle with sides of length 4 cm and 6 cm, and the included angle is 30 degrees, the area of the triangle would be:
Area = (1/2) * 4 cm * 6 cm * sin(30 degrees) = (1/2) * 24 cm^2 * 0.5 = 6 cm^2
If we have a triangle with sides of length 8 cm and 10 cm, and the included angle is 45 degrees, the area of the triangle would be:
Area = (1/2) * 8 cm * 10 cm * sin(45 degrees) = (1/2) * 80 cm^2 * 0.707 = 28.28 cm^2
This formula can be used to find the area of any triangle, given the lengths of two sides and the measure of the included angle.
How to find the area of a triangle given three sides?
To find the area of a triangle given its three sides, you can use Heron’s formula. This formula states that the area (A) of a triangle with sides of length a, b, and c is given by:
A = √(s(s  a)(s  b)(s  c))
where s is the semiperimeter of the triangle, defined as half the sum of its sides:
s = (a + b + c) / 2
To use Heron’s formula, simply plug in the values of the three sides of the triangle into the formula and calculate the result.
For example, let’s find the area of a triangle with sides of length 3, 4, and 5 units.
s = (3 + 4 + 5) / 2 = 6
A = √(6(6  3)(6  4)(6  5)) = √(6 * 3 * 2 * 1) = 6 square units
Therefore, the area of the triangle is 6 square units.
Heron’s formula is a versatile tool that can be used to find the area of any triangle, regardless of its shape or size. It is particularly useful when the triangle is not a right triangle, as it does not require knowledge of the triangle’s angles.
How to find the area of a triangle using vectors?
To find the area of a triangle using vectors, we can use the cross product of two vectors. The cross product of two vectors is a vector that is perpendicular to both of the original vectors. The magnitude of the cross product is equal to the area of the parallelogram formed by the two vectors.
If we have two vectors, a and b, then the cross product of a and b is defined as follows:
**a** x **b** = (a₂b₃  a₃b₂, a₃b₁  a₁b₃, a₁b₂  a₂b₁)
where a = (a₁, a₂, a₃) and b = (b₁, b₂, b₃).
To find the area of a triangle, we can use the cross product of two vectors that are parallel to two of the sides of the triangle. The magnitude of the cross product will then be equal to twice the area of the triangle.
For example, let’s say we have a triangle with vertices A(1, 2, 3), B(4, 5, 6), and C(7, 8, 9). We can find the area of this triangle using the following steps:
 Find two vectors that are parallel to two of the sides of the triangle. We can do this by subtracting the position vectors of two of the vertices. For example, we can find the vector AB by subtracting the position vector of A from the position vector of B:
**AB** = (4, 5, 6)  (1, 2, 3) = (3, 3, 3)
 Find the cross product of the two vectors. We can use the formula for the cross product to find the cross product of AB and AC:
**AB** x **AC** = (3, 3, 3) x (6, 6, 6) = (9, 9, 9)
 Find the magnitude of the cross product. The magnitude of the cross product is equal to the area of the parallelogram formed by the two vectors. In this case, the magnitude of the cross product is:
**AB** x **AC** = √((9)² + 9² + (9)²) = √243 = 9√3
 Divide the magnitude of the cross product by 2 to find the area of the triangle. The area of the triangle is:
Area = **AB** x **AC** / 2 = 9√3 / 2 = 4.5√3
Therefore, the area of the triangle is 4.5√3 square units.
How to calculate the area of a triangle?
Calculating the area of a triangle involves using specific formulas based on the given information about the triangle’s sides and angles. Here are the most common methods for calculating the area of a triangle:
1. Area Formula Using Base and Height:
 This formula is applicable when the base (b) and height (h) of the triangle are known.
 Formula: Area = (1/2) * b * h
 Example: If the base of a triangle is 6 cm and the height is 4 cm, then the area of the triangle is (1/2) * 6 cm * 4 cm = 12 cm².
2. Area Formula Using Two Sides and the Included Angle:
 This formula is used when two sides (a and b) of the triangle and the included angle (θ) between them are known.
 Formula: Area = (1/2) * a * b * sin(θ)
 Example: If two sides of a triangle are 5 cm and 7 cm, and the included angle is 30 degrees, then the area of the triangle is (1/2) * 5 cm * 7 cm * sin(30°) ≈ 8.66 cm².
3. Heron’s Formula:
 Heron’s formula is used when all three sides (a, b, and c) of the triangle are known.
 Formula: Area = √[s(s  a)(s  b)(s  c)]
 Here, s is the semiperimeter of the triangle, calculated as s = (a + b + c) / 2.
 Example: If the sides of a triangle are 4 cm, 6 cm, and 8 cm, then the semiperimeter is s = (4 cm + 6 cm + 8 cm) / 2 = 9 cm. Therefore, the area of the triangle is √[9 cm * (9 cm  4 cm) * (9 cm  6 cm) * (9 cm  8 cm)] ≈ 9.99 cm².
4. Area Formula Using Coordinates of Vertices:
 This method involves using the coordinates of the triangle’s vertices to calculate the area.
 Formula: Area = (1/2) * (x1 * (y2  y3) + x2 * (y3  y1) + x3 * (y1  y2))
 Here, (x1, y1), (x2, y2), and (x3, y3) are the coordinates of the three vertices of the triangle.
 Example: If the coordinates of the vertices are (2, 3), (4, 7), and (6, 2), then the area of the triangle is (1/2) * (2 * (7  2) + 4 * (2  3) + 6 * (3  7)) = 10 square units.
Remember that the units used for the sides and heights should be consistent throughout the calculations to obtain the area in the desired unit of measurement.